F(x)=x^2+x+20

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Solution for F(x)=x^2+x+20 equation: 



(F)=F^2+F+20

We move all terms to the left:

(F)-(F^2+F+20)=0

We get rid of parentheses

-F^2+F-F-20=0

We add all the numbers together, and all the variables

-1F^2-20=0

a = -1; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·(-1)·(-20)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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